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versionCompare.ml1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151(******************************************************************************) (* This file is part of the Dose library http://www.irill.org/software/dose *) (* Copyright (C) 2011 Ralf Treinen <ralf.treinen@pps.jussieu.fr> *) (* This library is free software: you can redistribute it and/or modify *) (* it under the terms of the GNU Lesser General Public License as *) (* published by the Free Software Foundation, either version 3 of the *) (* License, or (at your option) any later version. A special linking *) (* exception to the GNU Lesser General Public License applies to this *) (* library, see the COPYING file for more information. *) (* Work developed with the support of the Mancoosi Project *) (* http://www.mancoosi.org *) (******************************************************************************) let is_digit = function '0'..'9' -> true | _ -> false (* [skip_while_from i f w m] yields the index of the leftmost character * in the string [s], starting from [i], end ending at [m], that does * not satisfy the predicate [f], or [length w] if no such index exists. *) let skip_while_from i f w m = let rec loop i = if i = m then i else if f w.[i] then loop (i + 1) else i in loop i (* splits a version into (epoch,rest), without the separating ':'. The * epoch is delimited by the leftmost occurrence of ':' in x, and is "" * in case there is no ':' in x. *) let extract_epoch x = try let ci = String.index x ':' in let epoch = String.sub x 0 ci and rest = String.sub x (ci + 1) (String.length x - ci - 1) in (epoch, rest) with Not_found -> ("", x) (* splits a version into (prefix,revision). The revision starts on the * right-most occurrence of '-', or is empty in case the version does * not contain '-'. *) let extract_revision x = try let di = String.rindex x '-' in let before = String.sub x 0 di in let after = String.sub x (di + 1) (String.length x - di - 1) in (before, after) with Not_found -> (x, "") (* character comparison uses a modified character ordering: '~' first, then letters, then anything else *) let compare_chars c1 c2 = match c1 with | '~' -> ( match c2 with '~' -> 0 | _ -> -1 ) | 'a'..'z' | 'A'..'Z' -> ( match c2 with | '~' -> 1 | 'a'..'z' | 'A'..'Z' -> Char.compare c1 c2 | _ -> -1 ) | _ -> match c2 with '~' | 'a'..'z' | 'A'..'Z' -> 1 | _ -> Char.compare c1 c2 (* return the first index of x, starting from xi, of a nun-null * character in x. or (length x) in case x contains only 0's starting * from xi on. *) let skip_zeros x xi xl = skip_while_from xi (fun c -> c = '0') x xl (* compare versions chunks, that is parts of version strings that are * epoch, upstream version, or revisision. Alternates string comparison * and numerical comaprison. *) let compare_chunks x y = (* x and y may be empty *) let xl = String.length x and yl = String.length y in let rec loop_lexical xi yi = assert (xi <= xl && yi <= yl) ; match (xi = xl, yi = yl) with (* which of x and y is exhausted? *) | true, true -> 0 | true, false -> (* if y continues numerically than we have to continue by * comparing numerically. In this case the x part is * interpreted as 0 (since empty). If the y part consists * only of 0's then both parts are equal, otherwise the y * part is larger. If y continues non-numerically then y is * larger anyway, so we only have to skip 0's in the y part * and check whether this exhausts the y part. *) let ys = skip_zeros y yi yl in if ys = yl then 0 else if y.[ys] = '~' then 1 else -1 | false, true -> (* symmetric to the preceding case *) let xs = skip_zeros x xi xl in if xs = xl then 0 else if x.[xs] = '~' then -1 else 1 | false, false -> (* which of x and y continues numerically? *) match (is_digit x.[xi], is_digit y.[yi]) with | true, true -> (* both continue numerically. Skip leading zeros in the * remaining parts, and then continue by * comparing numerically. *) compare_numerical (skip_zeros x xi xl) (skip_zeros y yi yl) | true, false -> (* '~' is smaller than any numeric part *) if y.[yi] = '~' then 1 else -1 | false, true -> (* '~' is smaller than any numeric part *) if x.[xi] = '~' then -1 else 1 | false, false -> (* continue comparing lexically *) let comp = compare_chars x.[xi] y.[yi] in if comp = 0 then loop_lexical (xi + 1) (yi + 1) else comp and compare_numerical xi yi = assert (xi = xl || (xi < xl && x.[xi] <> '0')) ; (* leading zeros have been stripped *) assert (yi = yl || (yi < yl && y.[yi] <> '0')) ; (* leading zeros have been stripped *) let xn = skip_while_from xi is_digit x xl (* length of numerical part *) and yn = skip_while_from yi is_digit y yl (* length of numerical part *) in let comp = compare (xn - xi) (yn - yi) in if comp = 0 then (* both numerical parts have same length: compare digit by digit *) loop_numerical xi yi yn else (* if one numerical part is longer than the other we have found the * answer since leading 0 have been striped when switching * to numerical comparison. *) comp and loop_numerical xi yi yn = assert (xi <= xl && yi <= yn && yn <= yl) ; (* invariant: the two numerical parts that remain to compare are of the same length *) if yi = yn then (* both numerical parts are exhausted, we switch to lexical comparison *) loop_lexical xi yi else (* both numerical parts are not exhausted, we continue comparing digit by digit *) let comp = Char.compare x.[xi] y.[yi] in if comp = 0 then loop_numerical (xi + 1) (yi + 1) yn else comp in loop_lexical 0 0 let compare (x: string) (y: string) = let normalize_comp_result x = if x = 0 then 0 else if x < 0 then -1 else 1 in if x = y then 0 else let e1, rest1 = extract_epoch x and e2, rest2 = extract_epoch y in let e_comp = compare_chunks e1 e2 in if e_comp <> 0 then normalize_comp_result e_comp else let u1, r1 = extract_revision rest1 and u2, r2 = extract_revision rest2 in let u_comp = compare_chunks u1 u2 in if u_comp <> 0 then normalize_comp_result u_comp else normalize_comp_result (compare_chunks r1 r2) let equal (x: string) (y: string) = if x = y then true else compare x y = 0